WGU Foundations-of-Programming-Python Q&A - in .pdf

  • Foundations-of-Programming-Python pdf
  • Exam Code: Foundations-of-Programming-Python
  • Exam Name: Foundations of Programming (Python) - E010 JIV1
  • Updated: Oct 03, 2026
  • Q & A: 62 Questions and Answers
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  • Exam Code: Foundations-of-Programming-Python
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  • Q & A: 62 Questions and Answers
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  • Exam Name: Foundations of Programming (Python) - E010 JIV1
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  • Q & A: 62 Questions and Answers
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WGU Foundations-of-Programming-Python Exam Syllabus Topics:
SectionWeightObjectives
Topic 1: Control Flow and Decision Making20%- Conditional expressions
- If, elif, else statements
- Comparisons and logical operators
Topic 2: Data Structures and Input/Output20%- Basic file handling
- User input and output operations
- Lists, tuples, dictionaries, sets
Topic 3: Loops and Iteration20%- Iterating over sequences
- Break, continue, and pass statements
- For loops and while loops
Topic 4: Functions and Modular Programming20%- Parameters, arguments, and return values
- Variable scope and code reuse
- Defining and calling functions
Topic 5: Variables, Data Types, and Basic Operations20%- Arithmetic operations and type conversion
- Data types: integers, floats, strings, booleans
- Variables and assignment
WGU Foundations of Programming (Python) - E010 JIV1 Sample Questions:
Question #1

What distinguishes a terminal-based Python environment from other development environments?

  • A. Required internet connectivity for operation
  • B. Text-based command line interface
  • C. Automatic file saving capabilities
  • D. Graphical user interface elements
Reveal Solution  Discussion  0

Correct Answer: B  🗳️

Explanation: Only visible for ActualCollection members. You can sign-up / login (it's free).

Question #2

Which index position is returned when the string method .find( ' python ' ) is applied to the string ' learning python programming ' ?

  • A. 9
  • B. 8
  • C. 1
  • D. 2
Reveal Solution  Discussion  0

Correct Answer: A  🗳️

Explanation: Only visible for ActualCollection members. You can sign-up / login (it's free).

Question #3

Complete the function get_second_item(items) that takes a list and returns the second item. Assume the input is always a list containing at least two elements.
For example, get_second_item([10, 20, 30]) should return 20.
def get_second_item(items):
# TODO: Return the second item from the list
pass

Reveal Solution  Discussion  0

Correct Answer:

See the Step by Step Solution below in Explanation.
Explanation:
Step 1: Python list indexing starts at 0.
Step 2: The first item is at index 0.
Step 3: The second item is at index 1.
Step 4: Return the value at index 1.
Correct code:
def get_second_item(items):
return items[1]
Example:
print(get_second_item([10, 20, 30]))
Output:
20

Question #4

Complete the function add_item(numeric_list, new_number) that takes a list of numbers and a new number, and returns a new list that appends the new number to the end of the list.
For example, add_item([1, 2, 3], 4) should return [1, 2, 3, 4] .

  • A. def add_item(numeric_list, new_number):numeric_list.remove(new_number)return numeric_list
  • B. def add_item(numeric_list, new_number):return new_number
  • C. def add_item(numeric_list, new_number):numeric_list.append(new_number)return numeric_list
  • D. def add_item(numeric_list, new_number):pass
Reveal Solution  Discussion  0

Correct Answer: C  🗳️

Explanation: Only visible for ActualCollection members. You can sign-up / login (it's free).

Question #5

Fix the indexing error in this function that should return the last character of a string.
def get_last_character(text):
return text[len(text)]

Reveal Solution  Discussion  0

Correct Answer:

See the Step by Step Solution below in Explanation.
Explanation:
Step 1: Python string indexing starts at 0.
Step 2: The last valid index of a string is len(text) - 1, not len(text).
Step 3: Python also allows negative indexing, where -1 means the last character.
Step 4: Replace text[len(text)] with text[-1] .
Correct code:
def get_last_character(text):
return text[-1]
Example:
print(get_last_character( " Python " ))
Output:
n

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